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5=2+3.3x-0.75x^2
We move all terms to the left:
5-(2+3.3x-0.75x^2)=0
We get rid of parentheses
0.75x^2-3.3x-2+5=0
We add all the numbers together, and all the variables
0.75x^2-3.3x+3=0
a = 0.75; b = -3.3; c = +3;
Δ = b2-4ac
Δ = -3.32-4·0.75·3
Δ = 1.89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3.3)-\sqrt{1.89}}{2*0.75}=\frac{3.3-\sqrt{1.89}}{1.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3.3)+\sqrt{1.89}}{2*0.75}=\frac{3.3+\sqrt{1.89}}{1.5} $
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